Question

Find the real number solutions:
4w^4+40w^2-44=0
So far i have: 4(w^4+10w^2-11)=0
Need the steps, thanks!

Answer 1

4(w^4+10w^2-11)=0
4(w^2+11)(w^2-1)=0
because the first set of parentheses yield an imaginary answer, we only have
\[w=\left\{ -1,1, \right\}\]