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Mathematics 9 Online
OpenStudy (anonymous):

Solve for x in the proportion: **ATTACHED**

OpenStudy (anonymous):

OpenStudy (anonymous):

4x^3=16x^2-16x. 4x^3-16x^2+16x. Factor out a 4x(x^2-4x+4). Factoring that is 4x(x-2)(x-2). Setting each term equal to 0 and x=0 and 2.

OpenStudy (anonymous):

4x^3 = 16x^2 - 16x x^3 = 4x^2 - 4x x (x^2 - 4x + 4) = 0 x = 2 x = 0 would make the fraction indeterminate so x=2 is only valid answer

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