Question

The measures of three sides of a triangle are consecutive odd integers. The perimeter of the triangle is 57. What are the measures of the three sides?

Answer 1

Let teh numbers be A,B,C then we can assign values
A=x
B=x+2
C=x+4

we know A+B+C=57 by definition of perimiter, so then

x+ (x+2) + (x+4) = 57

3x = 57-6
x = 51/3
x= 17

now then
A =17, B=19, C=21