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Calculate the derivative of y with respect to x. x2 y + 2 x y2 = x + y
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and those are squared exp
X^2 + 4xy = x
\[x^2 y + 2 x y^2 = x + y\]implicit right?
Yep it is implicits
differentiate implicitly with product and chain rules:\[2xy+x^2y'+4xyy'+2y^2=1+y'\]collect our y's on one side:\\[2xy+2y^2-1=y'-x^2y'-4xyy'=y'(1-x^2-4xy)\]solve for y'\[y'={2xy+2y^2-1\over1-x^2-4xy}\]
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