Question

3x^2-5x-12=0

Answer 1

oh ouch...factoring...i was never any good at this:P

Answer 2

{{x = -4/3}, {x = 3}}

Answer 3

\[3x ^{2}-5x-12\]
multiply 3 to 12 and rewrite (this is an old jedi trick)
\[x ^{2}-5x-36\]
(x-9)(x+4)
Put 3 back in by dividing since we removed it by multiplying
(x-(9/3))(x+(4/3))
(x-3)(x+(4/3)
or (x-3)(3x+4)