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solve the equation (3k+4)^2=64
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solve it like this (3k+4)(3k+4)=64
what s the answer?
-4,4/3
Thanks!!!
(3k+4)2=(3k+4)(3k+4)=64=8 squared than 3k+4=8 3k=4 k= 4/3
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so prove the (-4) than
f(-4)=(3(-4)+4)^2=64 =(-12+4)^2=64 =(8)^2 =64 64=64 (this proves -4 for you jhonny9) this is a weird question
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