Question

determine the roots of
f(t)=9t^3-18t^2+6t
what is the quadratic formula for finding the roots?

Answer 1

the formula is

x = -b +-sqrt(b^2 - 4ac)
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2a

where a,b and c are the values in the equatioin

ax^2 + bx + c = 0

as before
t = 0
3t^2 - 6x + 2 = 0

so a = 3, b = -6 and c = 2
plug these values in the above formula to get the roots