selby walked for a while at 4mph and jogged the rest of the way at 8 mph. if she covered 56 miles in 10 hours how far did she walk and how far did she jog?

Question

selby walked for a while at 4mph and jogged the rest of the way at  8 mph. if she covered 56 miles in 10 hours how far did she walk and how far did she jog?

zarkon · Answer

solve

$$\frac{x}{4}+\frac{y}{8}=10$$
$$x+y=56$$
x=walking miles and y=jogging miles

anonymous · Answer

let the distance walked at rate of 4 mph = x miles
 => time taken to cover x miles = t1 = x/4 h

also distance jogged at 8 mph = (56 - x)  miles
=> time taken to cover (56 - x) miles = t2 = (56 - x)/8 h

total time = t1 + t2
so          x           56 - x
10 = ------ + -------
             4                 8

solve this for x and you will get yr answer....

anonymous · Answer

x           56 - x
10 = ------ + -------
             4                 8

80 = 2x + 56 - x
80 - 56 = x
24 = x

anonymous · Answer

willyg - see the question about buses