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simplify 18y^3 over 36xy^2 A 1/2x B y/2x C y^2/2x D 1/2xy
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\[\frac{18y^3}{36y^2}= \frac{1y^3}{2y^2}=\frac{1y^{3-2}}{2}=\frac{1y^1}{2}=\Large \frac y2\]
y/2x http://mathway.com/math_image.aspx?p=SMB02FSMB03ySMB102xSMB02fSMB03?p=26?p=42
sorry, that's y/2x
Answer B
\[\frac{18y^3}{36xy^2}= \frac{1y^3}{2xy^2}=\frac{1y^{3-2}}{2x}=\frac{1y^1}{2x}=\Large \frac {y}{2x}\]
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