Question

Use Newton's method to approximate the indicated root of the equation correct to six decimal places.
The positive root of
6sin x = x2

Answer 1

\[X _{1} = X _{0} - f(X _{0}) / f \prime( X _{0})\]
f(x) = 6 sin x- x^2
f'(x) = 6 cos x - 2x

try 0.5 as initial guess and insert to the equation