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Mathematics 8 Online
OpenStudy (anonymous):

need help on the attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

I got 3(x-3)-(x-4)/3(x-3)^(2/3), but my answer doesn't match any of the answer choices

OpenStudy (anonymous):

number 2 is correct for prob like this: use http://www.numberempire.com/derivatives.php dont let your teacher know about this website....

OpenStudy (anonymous):

how would I input the question into there

OpenStudy (anonymous):

number 2 is correct for prob like this: use http://www.numberempire.com/derivatives.php dont let your teacher know about this website....

OpenStudy (anonymous):

put in (x+4)(x-3)^(1/3)

OpenStudy (anonymous):

can it show you the work how they got it

OpenStudy (anonymous):

sure, use product rule: \[((x+4)(x-3)^{1/3})' = ((x-3)^{1/3}) + (x+4) \frac{1}{3} (x-3)^{-\frac{2}{3}}\] \[= (3(x-3)^{2/3} ((x-3)^{1/3}) + (x+4) ) * \frac{1}{3} (x-3)^{-\frac{2}{3}}\] \[=(4x-5 ) * \frac{1}{3} (x-3)^{-\frac{2}{3}}\]

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