Question

a pebble is dropped from the to of a building into a pool at ground level. how high is the building if the splash is seen 9 seconds after the weight is dropped. what is the velocity of the weight when it hits the ground?

Answer 1

Vi=0
Vf=?
t=9s
g=9.81m/s

x=(vi)t+(1/2)at^2
Vf=vi+at

Answer 2

thank you!

Answer 3

The g and a variable are interchangeable and remember that acceleration is meters per second squared.