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Mathematics 21 Online
OpenStudy (anonymous):

Prove the identity 2sin^-1x=cos^-1(1-2x^2)

OpenStudy (turingtest):

\[2\sin^{-1}(x)=\cos^{-1}(1-2x)\] Right? I just wanted to post it more clearly.

OpenStudy (anonymous):

Forgot the 2x^2 on your inverse cos equation

OpenStudy (zarkon):

differentiate both functions

OpenStudy (anonymous):

Yes that is the proper function, I've derived both sides, but i can't seem to get through the simplificatins

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