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Prove the identity 2sin^-1x=cos^-1(1-2x^2)
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\[2\sin^{-1}(x)=\cos^{-1}(1-2x)\] Right? I just wanted to post it more clearly.
Forgot the 2x^2 on your inverse cos equation
differentiate both functions
Yes that is the proper function, I've derived both sides, but i can't seem to get through the simplificatins
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