Question

Find the smallest of three consecutive integers such that 8 more than the product of the first and second is equal to the product of the second and third.

Answer 1

8+ab=bc
a+1=b
b+1=c
solve the system of equations

Answer 2

8+(n*(n+1))=(n+1)(n+2)
solve for n

where n is an integer and your three consecutive integers are
n, n+1 and n+2.