Find the tangent line for y = x^3 at 0. Does the tangent line cross the curve y = x^3 at the point of contact
i think its 0- what do they mean by point of contact
point of contact means where the two graphs intersect?
it seems obvious that they intersect at the point of contact
\[ y = x^3\rightarrow{dy \over dx}=3x^2\]o is correct the point crosses the curve because it is y^3, if it was y^2 it would not cross it, it would just touch it.
right X^3
|dw:1319137952826:dw|so along y=0 we will cross this graph
point of contact means where the two graphs intersect?
can you show by letting x^3 = 3x^2 then solve for x also?
so you think thats what they mean by cross? means not just touching?
if it was y=x^2 it would look like|dw:1319138039584:dw|so y=0 would only TOUCH the graph, not cross it
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