Question

3(k-2)=2(k+2)+k

Answer 1

3k-6=2k+4+k. 3k-6=3k+4. 0=10. Is this true, no it's false so No real solution.

Answer 2

3k-6=2k+4+k from distributing, then combine like terms
3k-6=3k+4 add 6 and sub 3k from both
0 = 10 This is not a function.