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OpenStudy (anonymous):
(10x^2+5xy)-(2xy-y^2) FACTOR PLEASE
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OpenStudy (anonymous):
5x(2x+y)-+y(2x-y) I think that's all. I was thinking about making the 2x-y common between them but I don't think that will work.
OpenStudy (anonymous):
5x(2x+y)-y(2x-y) 10x^2+y^2+3xy
OpenStudy (anonymous):
THANKS
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