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Show the solution of 9 – c < 2 and –3c > 15?
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We can treat the < and > like = signs. 9 - c < 2 -c < -7 Dividing by a negative flips the inequality. c > 7 The other one is: -3c > 15 Dividing through by -3, we flip the inequality. c < -5 I believe this is right. It has been a long time since I have done inequalities.
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