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evaluate \[\sum_{n=1}^{\infty}{(2(0.1)^n+(0.2)^n)}\]
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both geometric ..: 2 * (0.1)^n = 2 * (1/(1-(0.1))) = 2 2/9 (2/10)^n = (1/5)^n = 1/(1-(1/5)) = 1.25 add: 3 17/36
is it good ?
yes I got \[\frac{17}{36}\]as well
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