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Mathematics 18 Online
OpenStudy (anonymous):

FIND THE NUMBER abcde where a=b^2 b+c =10 d=b+1 c+e=11

OpenStudy (anonymous):

is it 42833??? i'm just guessing :P

OpenStudy (anonymous):

one of the ans!!!!! great!!!

OpenStudy (anonymous):

i suppode u had considered b=2 right

OpenStudy (anonymous):

yeahh. lemme try again. how about, 93744??

OpenStudy (anonymous):

ya it is!!!

OpenStudy (anonymous):

@agdg: what about ur answer!!!!!

OpenStudy (anonymous):

brute forcing it.....

OpenStudy (anonymous):

any other answers, dhashni???? give me a few. 11922???

OpenStudy (anonymous):

u have given all the ans !!! if we consider b=4 then 'a' becomes a 2 digit number which is not possible!!!

OpenStudy (anonymous):

exactly what i thought of.

OpenStudy (anonymous):

here are all the answers: 11922, 42833, 93744

OpenStudy (anonymous):

damn logic errors.... you guys beat me to them :-(

OpenStudy (anonymous):

hahahahahaha XD

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