Question

We know the following about the function g:

g(0)=0 g(1)=-1 g(2)=3 g(3)=2 g(4)=-2
g'(0)=1 g'(1)=2 g'(2)=0 g'(3)=4 g'(4)=-1

We define a new function h by the equation h(x)= gx^2-1). Find the equation of the line tangent to the graph of h at the point with x-coordinate 2.