Question

6q^2+13qw+6w^2

Answer 1

6q^2+9qw+4qw+6w^2=3q(2q+3w)+2w(2q+3w)=(3q+2w)(2q+3w)

Answer 2

what the eff is all that!! lol

Answer 3

same idea as before


multiply the first and last coefficients (6 and 6) to get 6*6 = 36


now you need to find two numbers that multiply to 36 and add to 13 (the middle coefficient)


These two numbers are 9 and 4


So this means that we replace 13qw with 9qw+4qw to get


6q^2+13qw+6w^2


6q^2+9qw+4qw+6w^2


Now factor by grouping



6q^2+9qw+4qw+6w^2


(6q^2+9qw)+(4qw+6w^2)


3q(2q+3w)+(4qw+6w^2)


3q(2q+3w)+2w(2q+3w)


(3q+2w)(2q+3w)



So 6q^2+13qw+6w^2 completely factors to (3q+2w)(2q+3w)


In other words, 6q^2+13qw+6w^2 = (3q+2w)(2q+3w)

Answer 4

ok, so what multiplies to 36 and adds up to 13. 9 and 4 and just treat it like before but mind the extra variable.