Question

3s^2-24s+48

Answer 1

given\[3s^2-24s+48\]factor out the common 3\[=3(s^2-8s+16)\]inside the parentheses is similar to your last posting\[=3(x-4)^2\]since -4*-4=16 and -4-4=-8

Answer 2

3(s^2-8s+16) = 3(s-4)(s-4)

Answer 3

\[3(s^2-8s+16)--->3(s-4)(s-4)--->\]
Then
=3(x−4)2
since -4*-4=16 and -4-4=-8