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Mathematics 10 Online
OpenStudy (anonymous):

graph y=x2 and it inverse

OpenStudy (anonymous):

is that a square? If so,

OpenStudy (precal):

switch x and y \[x=y^2\] solve for y \[x=\pm \sqrt{y}\] Remember that y=x is the equation you have to graph to make sure both functions have symmetry.

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