Question

who has an Algebra 1 question

Answer 1

4x=2 how do i solve?

Answer 2

divide by 4 on both sides

Answer 3

then simplify

Answer 4

why can't i multiply both sides by 1/4 instead?

Answer 5

?????

Answer 6

lol

Answer 7

i'm jk
is this consider an algebra1 question?

Answer 8

sure

Answer 9

it could be!!!

Answer 10

what is the difference btw algebra 1 and 2?

Answer 11

i was thinking if anybody needed help tho....

Answer 12

uhhh algebra 2 comes after geometry?!?!

Answer 13

you wanted to seem inviting

Answer 14

algebra 2 comes after geometry?

Answer 15

yea i figured tht out

Answer 16

yep it does!!

Answer 17

so you are talking about high school math

Answer 18

yea!!

Answer 19

i remember this now
i think it was:
algebra 1
geometry
algebra 2

Answer 20

yes it is!

Answer 21

why don't you want a more challenging question?
like a calculus problem?

Answer 22

b/c i am in 7th grade learning Algebra 1

Answer 23

oh i see

Answer 24

and i only kno algebra 1

Answer 25

ok how do i solve
\[a^2+2ab+b^2+4a+4b=-4\]
for a+b?

Answer 26

so the equation has to equal a+b?

Answer 27

here is an algebra question. prove A5 is simple

Answer 28

and what???? satellite? i am only gonna focus on one question at a time.... and tht is myin's

Answer 29

\[a^2+2ab+b^2=(a+b)^2\]
\[4a+4b=4(a+b)\]
\[(a+b)^2+4(a+b)=-4\]
\[(a+b)^2+4(a+b)+4=0\]

Answer 30

oh sorry. i will be quiet

Answer 31

now its ok cuz i dont get what the heck myin is sayin...

Answer 32

lol

Answer 33

A5 IS A times 5

Answer 34

asking you to solve that equation for a+b

Answer 35

ok now lemme get to work

Answer 36

\[(a+b+2)^2=0\]

Answer 37

\[a+b+2=0\]
you can solve this for a+b right?

Answer 38

yes!!! bbut i am on the first equation hold on

Answer 39

ok
\[a+b=-2 :)\]

Answer 40

o wait i am confused!!!??? on first equation solve for me??? too many numbers...... the one u just said isa+b=-2

Answer 41

\[a^2+2ab+b^2+4a+4b=-4\]
\[(a+b)^2+4a+4b=-4\]
\[(a+b)^2+4(a+b)=-4\]
\[(a+b)^2+4(a+b)+4=0\]
----------------------------
remember how to factor \[u^2+4u+4\]
\[(u+2)^2\]
----------------------------
\[(a+b+2)^2=0\]
\[a+b+2=0 => a+b=-2\]

Answer 42

do you guys factor in algebra 1?
solve equations in algebra 1?

Answer 43

we havent factored yet..

Answer 44

oh then thats the problem

Answer 45

ok try satellite's question whatever it was

Answer 46

i already did

Answer 47

is solve for x:
\[2x-1=7\] and algebra 1 question?
and if so how about
\[ax+b-c\]?

Answer 48

i meant
\[ax+b=c\]

Answer 49

x=4
c-b/a=x

Answer 50

ax=c-b
x=(c-b)/a

Answer 51

ok so i guess that takes care of that kind. how about
\[9x+5=7x+1\] or
\[ac+b=cx+d\]