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Mathematics 20 Online
OpenStudy (anonymous):

5a^3 + 35a^2 + 50a

myininaya (myininaya):

what is the gcf of 5a^3,35a^2,50a?

OpenStudy (anonymous):

I put 5

myininaya (myininaya):

they all have an a in common so we have \[5a \cdot a^2+5a \cdot 7a+5a \cdot 10\] \[=5a(a^2+7a+10)\] now you want to factor a^2+7a+10 by finding 2 factors of 10 that have product 10 and have sum 7

myininaya (myininaya):

10=2(5) 7=2+5

myininaya (myininaya):

\[5a(a^2+7a+10)=5a(a+2)(a+5)\]

myininaya (myininaya):

also=all type-0

OpenStudy (anonymous):

i dont understand

OpenStudy (ybarrap):

What steps are unclear?

jhonyy9 (jhonyy9):

gcf is 5a

jhonyy9 (jhonyy9):

subtract 5a from every terms and will get 5a(a2 +7a +10) - so but a2 +7a +10 = a2 +2a +5a +10 =a(a+2) + 5(a+2) =(a+2)(a+5) than we have 5a(a+2)(a+5)

jhonyy9 (jhonyy9):

than like solutions we get 5a=0 a=0 a+2=0 a= -2 a+5=0 a= -5

myininaya (myininaya):

you mean divide 5a from each term

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