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OpenStudy (anonymous):
write as a single logarithm a) log16+2log 3 b) log base 2 16 - 2logbase 2 3 c) 2+logbase 4 5
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OpenStudy (anonymous):
A, 2log3=log3^2=log9 log16+log9=log16*9=144 B, 2log(base2) 3=log(bas2)9 log(base2)16-log(base2)9=log(base2)16/9 C, 2=log(base 4)4^2 log(base4)16+log(base4)5=log(base4)80
OpenStudy (anonymous):
thank you andras!
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