Question

use the method of variation of parameters to find a particular solution of the given equation x^2y''-4xy'+6y=x^7 where y1 = x^2 and y2 = x^3 use the method of variation of parameters to find a particular solution of the given equation x^2y''-4xy'+6y=x^7 where y1 = x^2 and y2 = x^3 @Mathematics

Answer 1

i get y = x^6/12 + c1x^3 - c2x^2