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A stone is thrown upward from ground level. The initial speed is 320 feet per second. In how many seconds will the stone hit the ground?
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i assume the inital height is 0
and its in feet sooo -16t^2
-16t^2 + 320t is your position equation
when that bottoms out; the derivative is zero and that is half the time
or simply find the vertex axis at: -b/2a and twice it to get -b/a
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