Question

A stone is thrown upward from ground level. The initial speed is 128 feet per second. How high will it go?

Answer 1

use kinematic equation:
\[v_f^2=v_i^2+2a(y_f-y_i)\]
vf is zero at max hight, vi u know:

-vi^2/2a=(yf-yi)
yf-yi=-vi^2/2(-9.8)
h=835.91 feet

Answer 2

hold on leme give u the answer chocies

Answer 3

a) 288
b) 272
c) 256
d) 248
e) 264

Answer 4

non of above, it is 825.91 feet or 331 meters

Answer 5

well taht is not an asnwer choice so it has to b one of teh follwoeing