Question

Solve by subsitution
y= 2/3x-2
2x+3y=9

Answer 1

\[2x+3(\frac{2}{3}x -2) = 9\]
\[2x+2x -6 = 9\]
\[4x -6 = 9\]
\[4x = 15\]
\[x = \frac{15}{4}\]

plug it back into the first eq.

\[y = \frac{2}{3} \cdot \frac{15}{4} -2 \]
\[y = \frac{30}{12} -2 \]
\[y = \frac{5}{2} -\frac{4}{2} \]
\[y = \frac{1}{2} \]