Question

Solve for x (I'll post the equation below)

Answer 1

where?

Answer 2

[e^2x] - [4e^x] -5=0

Answer 3

that makes noooo sense O.o

Answer 4

logarithm

Answer 5

A quadratic in disguise! Let y = exp(x).
Then, the equation becomes \[y ^{2}-4y-5=0\]
Solves to (y-5)(y+1)=0, with solutions y=5, y=-1
So, exp(x)=5, -1, so inverse gives x=ln5 only, as ln(-1) undefined
Hope this helped.

Answer 6

That's what I thought but couldn't remember how to do it thanks!