Question

How to solve a system of equations

Answer 1

\[ x^2 - y^2 + \sqrt{x^2 + y^2} = 0 \]
\[2xy = 0 \]

Answer 2

If 2xy = 0 that means x = 0 , y = 0 or both x and y = 0.

Answer 3

So take the first equation and break it into three cases:

case 1: x = 0
case 2: y = 0
case 3: x = 0 and y = 0