Question

Can anybody explain to me how to solve quadratic functions ?

Answer 1

do you have any examples?

Answer 2

you can use quadratic formula

Answer 3

\[-b \pm \sqrt{b ^{2}-4ac} \over 2a\]a is the first number (it might be 1) b is the second, and c the third.

you can factor too.

Answer 4

Can yall explain how to factor polynomials?

Answer 5

You can factor the equation into f(x)=(x+s)(x+p) form

Answer 6

f(x)=ax^2+bx+c
You multiply a by c and you have to find two numbers that when you multiply them equals to a*c and when add them equals to b
For example 2x^2+7x+6:
2x6= 12 The numbers 3 and 4 when multiplied equals 12 and when added equals seven

Answer 7

The next step is to replace the middle terms with the two new terms
2x^2+4x+3x+6. Then you place brackets and then you factor
(2x^2+4x)(3x+6) Factor: 2x(x+2)+3(x+2)
If both of the insides of the brackets are the same which they should then you can gather the "like terms" : (2x+3) (x+2)=f(x)
You just gotta remember the steps

Answer 8

Factoring does not always work but the quadratic formula works 100% of the time. Factoring is faster than the quadratic formula.