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Mathematics
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divide 21x^3-50x^2-44x-8/7x+2
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factor the numerator out.
\[\frac{(7 x+2) (3 x^2-8 x-4)}{7x-2}\] \[\frac{\cancel{(7 x+2)} (3 x^2-8 x-4)}{\cancel{7x-2}}\] Finally..
\[3x^2 - 8x - 4\]
3x^2-8x-4
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