Question

6(3 - a) < 8a - 10
line under inequality sign

Answer 1

expand
18-6a=<8a-10

add 10
28-6a=<8a

add 6a
28=<14a

divide by 14
2=<a

Answer 2

\[6(3 - a) \le 8a - 10\]
\[18 - 6a \le 8a - 10\]
\[8a-10 \ge 18 -6a\]
\[8a + 6a \ge 18 + 10\]
\[14a \ge 28\]
\[a \ge2\]