Question

4x+4y= 2x^2, solve for x

Answer 1

4y=2x^2+4x

Answer 2

what does x =?

Answer 3

start with
\[2x^2-4x-4y=0\] then
\[x^2-2x-2y=0\] then either use the quadratic formula or complete the square

Answer 4

\[x^2-2x=2y\]
\[(x-1)^2=2y+1\]
\[x-1=\pm\sqrt{2y+1}\]
\[x=1\pm\sqrt{2y+1}\] is the complete the square method

Answer 5

Then do you use the FOIL method?

Answer 6

for quadratic equation?