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Mathematics 8 Online
OpenStudy (anonymous):

Differentiate the function y = f(x) = e^2xsquared+x. Differentiate the function y = f(x) = e^2xsquared+x. @Mathematics

OpenStudy (anonymous):

\[y=e ^{2x}+x\]\[y'=2e ^{2x}+1\]

OpenStudy (anonymous):

would it not be f'(x) = e^ u ( u')

OpenStudy (anonymous):

ya!!! thats why the '2' is multiplied with e^2x

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