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what is 3s^2+5s+2=0 ?????
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\[s = -1\] \[s = - \frac23\]
3s^2+5s + 2 = 0 3s^2 + 3s + 2s + 2 = 0 3s(s+1)+2(s+1) = 0 (s+1)(3s+2)=0 s = -1, -2/3
I hope that helps
Thanks, does the FOIL method work for that then?
I'm not a big fan of FOIL, but if you foil (s+1)(3s+2), you should get back to the original trinomial
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thanks a lot
Looks like Saifoo lost his Mod Status
i never got a mod status. :p
You did. You had it, you just never knew it. We were discussing this earlier.
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