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Given: f(x)=3x+2 g(x)=x/(x-3) Find (FoG)(x) and list the domain.
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f(g(x)) = 3(x/(x-3))+2
domain x cannot equal 3
and that's as simplified as it gets right.
h(x) = f(g(x)) = 3x/(x-3) + 2
so when i write it, it would look like this? \[\left(\begin{matrix}3x \\ x-3\end{matrix}\right)+2\]
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\[h(x) =f(g(x)) = \frac{3x}{x-3}+2\]
THANKS!
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