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find an angle such that 3 times the complement of the angle is 50 degrees greater than the supplement of the angle find an angle such that 3 times the complement of the angle is 50 degrees greater than the supplement of the angle @Mathematics
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I'm not positive, but I think you can set it up like this: Angle=x 3(90-x)-50=180-x Then solve for x
270-3x-50=180-x 40=2x x=20
let the angle be X 3(90-X) = (180-X) +50 solving X = 20
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