Question

I need help! D:
my problem is: what is the value of x1 in the equation y-6=1/2(x+2)

Answer 1

-2

Answer 2

can you please explain?

Answer 3

compare the above equation, with standard form ,
(y - y1) = m (x -x1)

Answer 4

:D THANK YOU SO SO MUCH!(:

Answer 5

If what you mean is
\[y-6=1/(2(x+2))\]
Multiply by (x+2) and divide by (y-6) on both sides
\[(y-6)(x+2)/(y-6)=(x+2)/(2(x+2)(y-6))\]
Cancel out what needs to be cancelled out:
\[(x+2)=1/(2(y-6))\]
Subtract 2 from both sides
\[x+2-2=(1/(2(y-6)))-2\]
\[x=(1/(2(y-6)))-2\]