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.... Find two consecutive even integers such that the smaller added to five times the larger gives a sum of 46.
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separate the answers with commas.
n+5(n+2)=46 solve for n and thats the smaller number
multiply 5 and 2 then divid by 46 im only guessing
distribute the 5 through n+2 n+5n+10=46 subtract 10 6n=36 divide by 6 n=6
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