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Mathematics 21 Online
OpenStudy (anonymous):

lx+3l<5

OpenStudy (anonymous):

x<2 x>-8

OpenStudy (anonymous):

-5<x+3<5 from def abs value -8<x<2 subtract 3 from all thre "sides" interval notation is (-8, 2)

OpenStudy (anonymous):

|x-a|<k where k is a postive number means the distance between x and a is less than k units

OpenStudy (anonymous):

in your exampel you want the x values that are less than 5 units from -3

OpenStudy (anonymous):

|dw:1319498803097:dw|

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