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x^2+53=0 I need to solve the equation. I need to type an exact answer using radicals as needed. The solution set is????? Need help.
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not possible, unless you are currently doing imaginary numbers?
is x a real or complex number? If x is real, then solution set is emty set
I can express in terms of i.
the x^2 = -53 x^2 = 53i^2 hence x = +/- ixsqrt(53)
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