Question

Compute the double integral over the region D where D is the triangle with vertices (0,0), (1,1) and (0,1).

{D} x\sqrt{y^2-x^2}\, dA

Answer 1

\[\int\limits_{0}^{1}\int\limits_{0}^{y}x\sqrt{y^2-x^2}dxdy=\frac{1}{12}\]