Question

x3+8x2+8x+64= factor by grouping

Answer 1

\[x^2(x+8)+8(x+8)\] is a start

Answer 2

\[8(x+8)+x^2(x+8)\]
\[(x+8) (x^2+8) \]

Answer 3

x^3+8x^2+8x+64



(x^3+8x^2)+(8x+64)



x^2(x+8)+8(x+8)



(x^2+8)(x+8)



So x^3+8x^2+8x+64 factors to (x^2+8)(x+8)



In other words, x^3+8x^2+8x+64=(x^2+8)(x+8)