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MIT 18.01 Single Variable Calculus (OCW)
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Integral xsqrt(9-16x^2) dx Integral xsqrt(9-16x^2) dx @MIT 18.01 Single …
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let u=9-16x^2 du=-32xdx \[\large{\frac{-1}{32} \int\limits{\sqrt{u}du} = \frac{-1}{32} (\frac{2}{3}) u^{\frac{3}{2}}}\]\[=\huge{\frac{-1}{48}} (9-16x^2)^{\frac{3}{2}}\]
i know how to do this, i was giving this as an example for someone
i know, i was trying to do it since no one tried
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