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Mathematics 16 Online
OpenStudy (anonymous):

factor completely 16a^4-1=

OpenStudy (anonymous):

(2a-1)*(2a+1)*(4a^2+1)

jimthompson5910 (jim_thompson5910):

16a^4-1 (4a^2)^2-1^2 (4a^2-1)(4a^2+1) ((2a)^2-1^2)(4a^2+1) (2a-1)(2a+1)(4a^2+1)

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