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let f(x)=1-2x^2 and g(x) = x+1 compute the following (f o g)(-1)
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the answr is 1
I got the correct answer I just need to make sure my steps are correct.
fg(x) is also (f o g)(x) but I'll just write it my way. \[fg(x)=-2x^{2}-4x-1\]\[fg(-1)=-2(-1)^{2}-4(-1)-1\]\[fg(-1)=1\]
where are you getting the 4
f(g(x)) = 1-2(x+1)^2 = 1-2*0^2 =1
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the steps are above
ok I got it thanks.
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